[linux-audio-dev] Problem and Solution: time

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Subject: [linux-audio-dev] Problem and Solution: time
From: Roger Larsson (roger.larsson_AT_norran.net)
Date: la tammi  08 2000 - 19:08:47 EST

Problem: how to express time, sample frequency and no of samples?

Possible solution:
  as a fraction of periods and sample frequency!
   periods / Hz
  both in 32 bit unsigned.

  s / 1 = s in seconds, range of over 100 years (like current time
handling in Unixes)

  n / f where
        n = no of samples in specified frequency
        f = frequency in HZ handles all sample frequencies up to 4 GHz ( < ns )
        

duration:
  (td*f) / f where td is duration in seconds
        with the maximum sample frequency the maximum duration is 1 s - ok
        with 96 kHz the maximum duration is 12 hours - ok
        with the minimum sample frequency (=1) the maximum duration is >100
years - ok

special:
  1 / 0 = one constant

/RogerL 

--
Home page:
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