Re: [LAD] jack client autoconnection (fwd)

Jonatan Liljedahl:
>>
>>
>> Thanks for clearing up. But I'm pretty sure your idea is too
>> simple. We also need a way to create ports which are not
>> autoconnected.
>>
>> The ideal way, if we follow this thread of thinking, would
>> be to add another type of jack_port_register function, which
>> does not autoconnect:
>>
>> jack_port_register_no_autoconnect(client,...);
>>
>> However, this new API will break a lot of current programs
>> which are using the old jack_port_register function instead.
>> Infact I don't think there is any (sane) way to make your
>> proposal work without creating lots of mess with ports
>> in old programs who are autoconnecting when it shouldn't.
>
> I think my proposal with a JackPortAutoConnect bit in JackPortFlags is
> sane, it would not break old applications; they would continue to
> function exactly as they are now. but updated code can get rid of their
> own autoconnection and use this autoconnect bit in the flags to
> jack_port_register() instead.
>

Yes, as long as JackPortAutoConnect is false by default, that's
definietely a sane solution. Its basically the same kind of
proposal I made, just using a flag to jack_port_register
instead of a new function.

But there is one problem with it:

jack_client_t *client=...
jack_port_t
   *out_port[0]=jack_port_register(client,...JackPortAutoConnect);
jack_port_t
   *out_port[1]=jack_port_register(client,...JackPortAutoConnect);

<something happens>

jack_port_t
   *new_out_port[0]=jack_port_register(client,...JackPortAutoConnect);
jack_port_t
   *new_out_port[1]=jack_port_register(client,...JackPortAutoConnect);

The problem is that new_out_port[0] and new_out_port[1] will
connect to physical port number 2 and 3 instead of 0 and 1.

How do you fix this problem without adding a new function to jacklib?

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Received on Mon Feb 4 20:15:04 2008