On 5/8/12, Paul Davis <paul@email-addr-hidden> wrote:
> what do you mean by "drop SMPTE frames" ?
>
Yes, I apologize, looking back, the question wasn't very clear.
Picture the following scenario.
I read the current jack frame (at the beginning of the process cycle,
say 'c') and convert it to SMPTE time, the result is
hh:mm:ss:n,
where n is some frame 'n'. The next time around the process cycle,
c+1, the current jack frame has advanced by a number equal to the
period size. An SMPTE frame occupies at least 1/30 seconds. If the
jack period size is equivalent to more than 1/30 seconds, then SMPTE
time at c+1 will have advanced to
hh:mm:ss:n+a,
where a > 1.
Thus, we have, effectively, skipped over the SMPTE frame n+1.
My question is whether the preceding is true.
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Received on Tue May 8 20:15:03 2012
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