On Mon, 30 Jan 2006 00:12:52 +0100
fons adriaensen <fons.adriaensen@email-addr-hidden> wrote:
> On Sun, Jan 29, 2006 at 10:55:05PM +0000, Folderol wrote:
>
> > No! It is definitely 1/c1 + 1/c2 ...
> >
> > The only alternative I know of is 'product divided by sum' which is
> > often easier to use.
> >
> > i.e.
> >
> > (c1 x c2 x c3) / (c1 + c2 + c3)
>
> Sorry, all wrong, as can be seen easily by considering the dimensions.
> The first one is 1/Farad, the second Farad^2.
>
> The rule is the same as for parallell resistors:
>
> The inverse of the equivalent value is the sum of the inverses
> of all individual values.
>
> 1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
>
> or for just two of them
>
> Ceq = (C1 * C2) / (C1 + C2)
Apologies. I'm out of practise :( I was *assuming* the 1/Ceq = and we
all know about when you ASS U ME. As you say the second one is
strictly for two components.
-- FReceived on Tue Jan 31 00:15:09 2006
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