Re: [LAU] Theramin oscillator for LADSPA?

On Sun, Oct 6, 2013 at 9:59 PM, Fons Adriaensen <fons@email-addr-hidden> wrote:

> #!/usr/bin/python
>
> from math import *
>
>
> X = [ 0.00, 0.70, 1.30, 2.00, 2.70, 3.25, 4.00, 4.65, 5.15, 5.85,
> 6.35, 6.95, 7.40, 7.95, 8.30, 8.75, 9.10, 9.55, 10.00, 10.25,
> 10.55, 10.90, 11.20, 11.53, 11.70, 11.40, 10.98, 10.10, 9.10, 8.00,
> 6.90, 5.75, 4.45, 3.20, 2.10, 1.01, 0.00, -1.00, -1.98, -2.90,
> -3.70, -4.25, -5.00, -5.60, -6.10, -6.60, -7.02, -7.35, -7.80, -8.00,
> -8.15, -8.30, -8.40, -8.46, -8.50, -8.50, -8.47, -8.45, -8.27, -8.10,
> -7.99, -7.80, -7.55, -7.25, -7.00, -6.67, -6.35, -6.05, -5.65, -5.30,
> -4.98, -4.50, -4.05, -3.60, -3.05, -2.60, -2.00, -1.45, -0.80 ]
>
> N = len(X)
>
> def analyse(f):
> sx = 0
> sy = 0
> w = f * 2 * pi / N
> for i in range(N):
> sx += X [i] * sin (i * w)
> sy += X [i] * cos (i * w)
> m = hypot (sx, sy)
> a = atan2(sy, sx) * 180 / pi
> return m, a
>
>
> for i in range (1, 11):
> m, a = analyse (i)
> if i == 1: m1 = m
> print ("%3d %10.3f %8.1f" % (i, m / m1, a))
>

Wauw, that's a golden nugget of Python! Cheers, -Harry

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Received on Mon Oct 7 08:15:06 2013