El 20/12/13 15:04, Clemens Ladisch escribió:
> With USB devices, the period boundaries (where interrupts are supposed
> to happen) are not necessarily coincident with the USB frame boundaries
> (where interrupts actually happen). This results in delays (jitter) of
> up to 1 ms in the timing of period interrupts; with very small buffer
> sizes, this increases the risk of underruns greatly. So if, e.g., the
> machine is not able to handle "-p 64 -n 2" reliably, increasing the
> number of periods to 3 results in lower latency (3*64=192) than
> increasing the period size (2*128=256). (Using "-p 96 -n 2" would have
> the same latency, but works only if that particular Jack version allows
> period sizes that are not a power of two.)
This is a great explanation. Thanks!
--
Roberto Suarez Soto I was born in the back of a black cadillac
And raised by a gypsy queen
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Received on Fri Dec 20 20:15:01 2013
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