Re: [LAU] Something odd

On Sat, Aug 15, 2015 at 10:27:33PM +0100, Will Godfrey wrote:
 
> As a matter of curiosity I wonder if we can work out what the actual difference
> is. Would the Xrun occur when there was a one frame difference, one period, or
> 1 buffer? It's running at 256 frames per period and 2 periods per buffer. The
> xruns occur every 11 minutes (and a few seconds).

If you assume that an xrun occurs when the difference in samples is
one period, then the difference in sample frequency is P / T, with
P the period and T the time in seconds between xruns.

With the values you give:

dF = 256 / (11 * 60) =~ 0.39 Hz.

You can measure this easily using jack_delay (or jack_iodelay).
The change in measured latency, in samples, per second is the
difference in sample rate.

Ciao,

-- 
FA
A world of exhaustive, reliable metadata would be an utopia.
It's also a pipe-dream, founded on self-delusion, nerd hubris
and hysterically inflated market opportunities. (Cory Doctorow)
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