fons adriaensen schrieb:
>On Sun, Jan 29, 2006 at 10:55:05PM +0000, Folderol wrote:
>
>
>
>>No! It is definitely 1/c1 + 1/c2 ...
>>
>>The only alternative I know of is 'product divided by sum' which is
>>often easier to use.
>>
>>i.e.
>>
>>(c1 x c2 x c3) / (c1 + c2 + c3)
>>
>>
>
>Sorry, all wrong, as can be seen easily by considering the dimensions.
>The first one is 1/Farad, the second Farad^2.
>
>The rule is the same as for parallell resistors:
>
> The inverse of the equivalent value is the sum of the inverses
> of all individual values.
>
> 1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
>
>or for just two of them
>
> Ceq = (C1 * C2) / (C1 + C2)
>
>
with 3 caps, it would be:
ceq = (c1*c2*c3) / (c2*c3 + c1*c3 + c1*c2)
Received on Mon Jan 30 04:15:14 2006
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